What is the answer to 1=sqrt(4-(x-3)^2) ?

The answer to 1=sqrt(4-(x-3)^2) is x=3-sqrt(3),x=3+sqrt(3)

Solve for x: 1=sqrt(4-(x-3)^2)

The solution is x=3-sqrt(3),x=3+sqrt(3)

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1 = 4 - (x - 3)^{2}

x = 3 - 3, x = 3 + 3

Decimal Notation

x = 1.26794 \dots, x = 4.73205 \dots

Solution steps

1 = 4 - (x - 3)^{2}

Square both sides:

1 = - x^{2} + 6 x - 5

1 = - x^{2} + 6 x - 5

Solve

1 = - x^{2} + 6 x - 5 : x = 3 - 3, x = 3 + 3

x = 3 - 3, x = 3 + 3

Verify Solutions:

x = 3 - 3

True

, x = 3 + 3

True

The solutions are

x = 3 - 3, x = 3 + 3

x + 6 = - 9

(\frac{x}{1 - x})^{0.4686} = 0.537

x = 2 - x^{4} - x^{3}

0.85 (1) = 1 1 - x^{2}

x^{2} - 2 x + 1 = 3 x + 2

What is the answer to 1=sqrt(4-(x-3)^2) ?
The answer to 1=sqrt(4-(x-3)^2) is x=3-sqrt(3),x=3+sqrt(3)
Solve for x: 1=sqrt(4-(x-3)^2)
The solution is x=3-sqrt(3),x=3+sqrt(3)