log_{5}(2x-4)=2

Lösung

lo g_{5} (2 x - 4) = 2

x = \frac{29}{2}

Dezimale

x = 14.5

Schritte zur Lösung

lo g_{5} (2 x - 4) = 2

Wende die log Regel an

2 x - 4 = 25

Löse

2 x - 4 = 25 : x = \frac{29}{2}

x = \frac{29}{2}

- 4 + lo g_{3} (x + 1) = - 3

lo g_{b} (125) = 3

ln (x) - \frac{3}{ln ( x )} = - 2

lo g_{e} (x) = 0

lo g_{x} (\frac{1}{64}) = - 2