What is the answer to 3log_{2/3}(x)+12=0 ?

The answer to 3log_{2/3}(x)+12=0 is x= 81/16

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3log_{2/3}(x)+12=0

3 lo g_{\frac{2}{3}} (x) + 12 = 0

x = \frac{81}{16}

Decimal Notation

x = 5.0625

Solution steps

3 lo g_{\frac{2}{3}} (x) + 12 = 0

Move

12

to the right side

3 lo g_{\frac{2}{3}} (x) = - 12

Divide both sides by

3

lo g_{\frac{2}{3}} (x) = - 4

Apply log rules

x = \frac{81}{16}

Verify Solutions:

x = \frac{81}{16}

True

The solution is

x = \frac{81}{16}

lo g_{2} (x + 7) - lo g_{2} (x - 11) = 2

lo g_{5} (x - 4) = 0

ln (3 x - 2) = 5

lo g_{16} (x) = \frac{1}{2}

lo g_{9} (y) - 2 = lo g_{3} (y)

What is the answer to 3log_{2/3}(x)+12=0 ?
The answer to 3log_{2/3}(x)+12=0 is x= 81/16
Solve for x: 3log_{2/3}(x)+12=0
The solution is x= 81/16