What is the answer to 3.82=-log_{10}(x) ?

The answer to 3.82=-log_{10}(x) is x= 1/(10^{3.82)}

Solve for x: 3.82=-log_{10}(x)

The solution is x= 1/(10^{3.82)}

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3.82 = - lo g_{10} (x)

x = \frac{1}{1 0 ^{3.82}}

Decimal Notation

x = 0.00015 \dots

Solution steps

3.82 = - lo g_{10} (x)

Move

lo g_{10} (x)

to the left side

3.82 + lo g_{10} (x) = 0

Move

3.82

to the right side

lo g_{10} (x) = - 3.82

Apply log rules

x = \frac{1}{1 0 ^{3.82}}

Verify Solutions:

x = \frac{1}{1 0 ^{3.82}}

True

The solution is

x = \frac{1}{1 0 ^{3.82}}

x^{2} ln (x) = 0

lo g_{6} (x) - lo g_{6} (x + 1) = 2

4 lo g_{10} (2 x - 2) = 2

lo g_{3} (2 x - 4) = 2

5 ln (2 x + 3) + 6 = 16

What is the answer to 3.82=-log_{10}(x) ?
The answer to 3.82=-log_{10}(x) is x= 1/(10^{3.82)}
Solve for x: 3.82=-log_{10}(x)
The solution is x= 1/(10^{3.82)}