solvefor x,y-2=ln(x+e^2)

Lösung

löse nach

x, y - 2 = ln (x + e^{2})

x = e^{y - 2} - e^{2}

Schritte zur Lösung

y - 2 = ln (x + e^{2})

Wende die log Regel an

e^{y - 2} = x + e^{2}

Löse

e^{y - 2} = x + e^{2} : x = e^{y - 2} - e^{2}

x = e^{y - 2} - e^{2}

lo g_{2} (x) - 3 lo g_{2} (x) = 6

lo g_{x} (2) = 0

lo g_{x} (2) = 5

3 + 2 ln (x^{2}) = 7

8 lo g_{2} (7 p - 5) - 4 = 28