solvefor x,y=ln(x-1)

Lösung

löse nach

x, y = ln (x - 1)

x = e^{y} + 1

Schritte zur Lösung

y = ln (x - 1)

Wende die log Regel an

e^{y} = x - 1

Löse

e^{y} = x - 1 : x = e^{y} + 1

x = e^{y} + 1

4 ln (6 x) = - 4

lo g_{x} (\frac{9}{4}) = 2

3 lo g_{10} (4 - x) = 1 - x

\frac{9}{8} lo g_{2} (x) = - 10

lo g_{a} (3) = 0.565