log_{3}((r+6)^2)=2

Lösung

lo g_{3} ((r + 6)^{2}) = 2

r = - 3, r = - 9

Schritte zur Lösung

lo g_{3} ((r + 6)^{2}) = 2

Wende die log Regel an

(r + 6)^{2} = 9

Löse

(r + 6)^{2} = 9 : r = - 3, r = - 9

r = - 3, r = - 9

lo g_{4} (x - 3) + lo g_{4} (x + 9) = 3

so l v e f or x, ln (3 x - 10) = 5

lo g_{x} (9) = 2

lo g_{2} (5 \cdot x) = 10

ln (b x) = - 1