log_{2}(3x+2)=1

Lösung

lo g_{2} (3 x + 2) = 1

x = 0

Schritte zur Lösung

lo g_{2} (3 x + 2) = 1

Wende die log Regel an

3 x + 2 = 2

Löse

3 x + 2 = 2 : x = 0

x = 0

4 ln (4 x) = - 4

f (x) x = 2 x^{3} ln (x)

lo g_{2} (x) = 0.96899

lo g_{10} (2 - x) = 2

2 ln (\frac{3 + 1}{x}) = 0.001