What is the answer to ln(x^4)-ln(x^2)-2=0 ?

The answer to ln(x^4)-ln(x^2)-2=0 is x=e,x=-e

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

ln(x^4)-ln(x^2)-2=0

ln (x^{4}) - ln (x^{2}) - 2 = 0

x = e, x = - e

Decimal Notation

x = 2.71828 \dots, x = - 2.71828 \dots

Solution steps

ln (x^{4}) - ln (x^{2}) - 2 = 0

Apply exponent rule:

a^{2 \cdot n} = (a^{2})^{n}

x^{4} = (x^{2})^{2}

ln ((x^{2})^{2}) - ln (x^{2}) - 2 = 0

Apply log rules

x^{2} = e^{2}

Solve

x^{2} = e^{2} : x = e, x = - e

x = e, x = - e

Verify Solutions:

x = e

True

, x = - e

True

The solutions are

x = e, x = - e

lo g_{x - 3} (x^{2} - 3 x - 4) = 2

ln (x) + ln (5 - 2 x) = 0

lo g_{6561} (N) = - \frac{3}{4}

lo g_{2} (x) - lo g_{2} (x - 2) = 4

x, ln (x) = a + b (ln (y))

What is the answer to ln(x^4)-ln(x^2)-2=0 ?
The answer to ln(x^4)-ln(x^2)-2=0 is x=e,x=-e
Solve for x: ln(x^4)-ln(x^2)-2=0
The solution is x=e,x=-e