ln(2x-1)=5

Lösung

ln (2 x - 1) = 5

x = \frac{e ^{5} + 1}{2}

Dezimale

x = 74.70657 \dots

Schritte zur Lösung

ln (2 x - 1) = 5

Wende die log Regel an

2 x - 1 = e^{5}

Löse

2 x - 1 = e^{5} : x = \frac{e ^{5} + 1}{2}

x = \frac{e ^{5} + 1}{2}

lo g_{2} (n) = 1000

10 lo g_{10} (x) = 108

a ln (a) - a \cdot 1 = 0

lo g_{10} (4 - 3 x) = 32

ln (17 x + 8) = 1