(1+i)x+(y+5)i=3(1-y)

解答

(1 + i) x + (y + 5) i = 3 (1 - y)

x = - 9, y = 4

求解步骤

(1 + i) x + (y + 5) i = 3 (1 - y)

将

(1 + i) x + (y + 5) i

改写成标准复数形式:

x + (x + y + 5) i

x + (x + y + 5) i = 3 (1 - y)

将

3 (1 - y)

改写成标准复数形式:

3 (1 - y) + 0 i

x + (x + y + 5) i = 3 (1 - y) + 0 i

复数仅在实部和虚部均相等时才相等改写为方程组:

[x = 3 (1 - y) x + y + 5 = 0]

[x = 3 (1 - y) x + y + 5 = 0] : x = - 9, y = 4

x = - 9, y = 4

(1 - i) x + (1 + i) y = 1 - 3 i

(x + i y)^{2} = i

(2 + 3 i) x - (1 + i) y = 3 + 4 i

a - bi = ai - b

p = i v