(a+i)(b-3i)=7-11i

解

(a + i) (b - 3 i) = 7 - 11 i

(a = 4, b = 1 a = - \frac{1}{3}, b = - 12)

解答ステップ

(a + i) (b - 3 i) = 7 - 11 i

拡張

(a + i) (b - 3 i) : (ab + 3) + i (b - 3 a)

(ab + 3) + i (b - 3 a) = 7 - 11 i

複素数は, その実数部と虚数部が等しい場合にのみ等しくなるequation系として書き換える:

[ab + 3 = 7 b - 3 a = - 11]

[ab + 3 = 7 b - 3 a = - 11] : (a = 4, b = 1 a = - \frac{1}{3}, b = - 12)

(a = 4, b = 1 a = - \frac{1}{3}, b = - 12)