4x+(y-3)i=20

解答

4 x + (y - 3) i = 20

x = 5, y = 3

求解步骤

4 x + (y - 3) i = 20

将

20

改写成标准复数形式:

20 + 0 i

4 x + (y - 3) i = 20 + 0 i

复数仅在实部和虚部均相等时才相等改写为方程组:

[4 x = 20 y - 3 = 0]

[4 x = 20 y - 3 = 0] : x = 5, y = 3

x = 5, y = 3

z - \frac{1}{z} = 5 + 3 i

(a - bi) (a + bi + 1) = 11 + 3 i

a (1 - 3 i) + b (4 - i) = - 17 - 4 i

(a + ib)^{2} = i

x - 2 y i = - 1 + 5 i