(3a+2i)-(5-2bi)=2-6i

解答

(3 a + 2 i) - (5 - 2 bi) = 2 - 6 i

a = \frac{7}{3}, b = - 4

求解步骤

(3 a + 2 i) - (5 - 2 bi) = 2 - 6 i

将

(3 a + 2 i) - (5 - 2 bi)

改写成标准复数形式:

(3 a - 5) + (2 + 2 b) i

(3 a - 5) + (2 + 2 b) i = 2 - 6 i

复数仅在实部和虚部均相等时才相等改写为方程组:

[3 a - 5 = 2 2 + 2 b = - 6]

[3 a - 5 = 2 2 + 2 b = - 6] : a = \frac{7}{3}, b = - 4

a = \frac{7}{3}, b = - 4

x^{2} - (1 + 2 i) x + (2 + i) = 0

\frac{5 + 2 i}{z} = 2 - i

(x - y) + 5 i = 2 + y i

(z + i) (z - 2 i) = z^{2} + i z + 2

(u - i) (4 + i v) = 11 + 2 i