(si)/(P(x))=(x-1)^2+x-1

解

\frac{s i}{P ( x )} = (x - 1)^{2} + x - 1

s = 0, s = 0, s = 0, x = 0, x \in R, x = 1, P \in R P = 0 P \in R

解答ステップ

\frac{s i}{P ( x )} = (x - 1)^{2} + x - 1

以下で両辺を乗じる:

P (x)

\frac{s i}{P ( x )} P (x) = (x - 1)^{2} P (x) + x P (x) - 1 \cdot P (x)

拡張

i s = x^{2} P (x) - x P (x)

標準的な複素数形式で

i s

を書き換える:

0 + s i

0 + s i = x^{2} P (x) - x P (x)

標準的な複素数形式で

x^{2} P (x) - x P (x)

を書き換える:

(x^{2} P (x) - x P (x)) + 0 i

0 + s i = (x^{2} P (x) - x P (x)) + 0 i

複素数は, その実数部と虚数部が等しい場合にのみ等しくなるequation系として書き換える:

[0 = x^{2} P (x) - x P (x) s = 0]

[0 = x^{2} P (x) - x P (x) s = 0] : s = 0, s = 0, s = 0, x = 0, x \in R, x = 1, P \in R P = 0 P \in R

s = 0, s = 0, s = 0, x = 0, x \in R, x = 1, P \in R P = 0 P \in R