(1-2+sqrt(7)i)(x)-2y=0

解答

(1 - 2 + 7 i) (x) - 2 y = 0

x = 0, y = 0

求解步骤

(1 - 2 + 7 i) (x) - 2 y = 0

将

(1 - 2 + 7 i) (x) - 2 y

改写成标准复数形式:

(- x - 2 y) + 7 x i

(- x - 2 y) + 7 x i = 0

将

0

改写成标准复数形式:

0 + 0 i

(- x - 2 y) + 7 x i = 0 + 0 i

复数仅在实部和虚部均相等时才相等改写为方程组:

[- x - 2 y = 0 7 x = 0]

[- x - 2 y = 0 7 x = 0] : x = 0, y = 0

x = 0, y = 0

m^{2} + n + 4 i = - 3 - m^{2} ni

\frac{a + 2 i}{b - 3 i} = 1 + i

(a + bi)^{2} = - 3 - 4 i

z^{2} - z = 5 - 5 i

(1 + 3 i) z^{2} + (5 + 6 i) z + 7 - 6 i = 0