2x^2-2x=0

解答

2 x^{2} - 2 x = 0

x = 1, x = 0

求解步骤

2 x^{2} - 2 x = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

(- 2)^{2} - 4 \cdot 2 \cdot 0 = 2

x_{1, 2} = \frac{- ( - 2 ) \pm 2}{2 \cdot 2}

将解分隔开

x_{1} = \frac{- ( - 2 ) + 2}{2 \cdot 2}, x_{2} = \frac{- ( - 2 ) - 2}{2 \cdot 2}

x = \frac{- ( - 2 ) + 2}{2 \cdot 2} : 1

x = \frac{- ( - 2 ) - 2}{2 \cdot 2} : 0

二次方程组的解是:

x = 1, x = 0

5 x^{2} - 20 x + 3 = 0

f a c t or 10 x^{2} + 2 x y - 15 x - 3 y

s im pl i f y \frac{m ^{\frac{2}{3}} n ^{2}}{m ^{- 1} n ^{3}}

7 (\frac{1}{2} x + 2) - 4 < - 5

f a c t or 36 a^{4} - 25 b^{4}