faktorisieren 36a^4-25b^4

Lösung

faktorisieren

36 a^{4} - 25 b^{4}

(6 a^{2} + 5 b^{2}) (6 a^{2} - 5 b^{2})

Schritte zur Lösung

36 a^{4} - 25 b^{4}

36 a^{4} = (6 a^{2})^{2}

25 b^{4} = (5 b^{2})^{2}

= (6 a^{2})^{2} - (5 b^{2})^{2}

Wende Formel zur Differenz von zwei Quadraten an:

x^{2} - y^{2} = (x + y) (x - y)

(6 a^{2})^{2} - (5 b^{2})^{2} = (6 a^{2} + 5 b^{2}) (6 a^{2} - 5 b^{2})

= (6 a^{2} + 5 b^{2}) (6 a^{2} - 5 b^{2})

(x - 2) (x + 4) = 0

r^{2} + 8 r + 32 = 0

11 x = 8 x - 6

52 = n - \frac{1}{5} n

s im pl i f y 4^{9}