What are the solutions to the equation 9n^2+6n+1=0 ?

The solutions to the equation 9n^2+6n+1=0 are n=-1/3

Find the zeros of 9n^2+6n+1=0

The zeros of 9n^2+6n+1=0 are n=-1/3

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9 n^{2} + 6 n + 1 = 0

n = - \frac{1}{3}

Decimal Notation

n = - 0.33333 \dots

Solution steps

9 n^{2} + 6 n + 1 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 9 \cdot 1}{2 \cdot 9}

6^{2} - 4 \cdot 9 \cdot 1 = 0

n_{1, 2} = \frac{- 6 \pm 0}{2 \cdot 9}

n = \frac{- 6}{2 \cdot 9}

\frac{- 6}{2 \cdot 9} = - \frac{1}{3}

n = - \frac{1}{3}

The solution to the quadratic equation is:

n = - \frac{1}{3}

\frac{e ^{t}}{e ^{2 t}}

e^{i \cdot \frac{π}{2}}

2 x^{2} - 11 x = 40

8 x^{2} + 6 x - 5

\frac{x + 5}{2} = 10

What are the solutions to the equation 9n^2+6n+1=0 ?
The solutions to the equation 9n^2+6n+1=0 are n=-1/3
Find the zeros of 9n^2+6n+1=0
The zeros of 9n^2+6n+1=0 are n=-1/3