What are the solutions to the equation 1-0.5x-0.4x^2=0 ?

The solutions to the equation 1-0.5x-0.4x^2=0 are x=-(5+sqrt(185))/8 ,x=(sqrt(185)-5)/8

Find the zeros of 1-0.5x-0.4x^2=0

The zeros of 1-0.5x-0.4x^2=0 are x=-(5+sqrt(185))/8 ,x=(sqrt(185)-5)/8

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1 - 0.5 x - 0.4 x^{2} = 0

x = - \frac{5 + 185}{8}, x = \frac{185 - 5}{8}

Decimal Notation

x = - 2.32518 \dots, x = 1.07518 \dots

Solution steps

1 - 0.5 x - 0.4 x^{2} = 0

Multiply both sides by

10

10 - 5 x - 4 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 4 x^{2} - 5 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 ( - 4 ) \cdot 10}{2 ( - 4 )}

(- 5)^{2} - 4 (- 4) \cdot 10 = 185

x_{1, 2} = \frac{- ( - 5 ) \pm 185}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 185}{2 ( - 4 )}, x_{2} = \frac{- ( - 5 ) - 185}{2 ( - 4 )}

x = \frac{- ( - 5 ) + 185}{2 ( - 4 )} : - \frac{5 + 185}{8}

x = \frac{- ( - 5 ) - 185}{2 ( - 4 )} : \frac{185 - 5}{8}

The solutions to the quadratic equation are:

x = - \frac{5 + 185}{8}, x = \frac{185 - 5}{8}

4 = - 8 x^{2} + 8 x + 10

x^{2} + 10 x = - 1

a^{2} + 2 ab + b^{2} - x^{2}

3.02 x^{2} + 16 x - 7.02 = 0

x^{2} + x - 12 = x + 4

What are the solutions to the equation 1-0.5x-0.4x^2=0 ?
The solutions to the equation 1-0.5x-0.4x^2=0 are x=-(5+sqrt(185))/8 ,x=(sqrt(185)-5)/8
Find the zeros of 1-0.5x-0.4x^2=0
The zeros of 1-0.5x-0.4x^2=0 are x=-(5+sqrt(185))/8 ,x=(sqrt(185)-5)/8