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受欢迎的代数 >

9p^2+6p+1=12

解答

9 p^{2} + 6 p + 1 = 12

解答

p = \frac{- 1 + 2 3}{3}, p = - \frac{1 + 2 3}{3}

+1

十进制

p = 0.82136 \dots, p = - 1.48803 \dots

求解步骤

9 p^{2} + 6 p + 1 = 12

将

12

para o lado esquerdo

9 p^{2} + 6 p - 11 = 0

使用求根公式求解

p_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 9 ( - 11 )}{2 \cdot 9}

6^{2} - 4 \cdot 9 (- 11) = 123

p_{1, 2} = \frac{- 6 \pm 12 3}{2 \cdot 9}

将解分隔开

p_{1} = \frac{- 6 + 12 3}{2 \cdot 9}, p_{2} = \frac{- 6 - 12 3}{2 \cdot 9}

p = \frac{- 6 + 12 3}{2 \cdot 9} : \frac{- 1 + 2 3}{3}

p = \frac{- 6 - 12 3}{2 \cdot 9} : - \frac{1 + 2 3}{3}

二次方程组的解是:

p = \frac{- 1 + 2 3}{3}, p = - \frac{1 + 2 3}{3}

作图

流行的例子

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