What are the solutions to the equation x^2+36x+332=0 ?

The solutions to the equation x^2+36x+332=0 are x=-18+2sqrt(2)i,x=-18-2sqrt(2)i

Find the zeros of x^2+36x+332=0

The zeros of x^2+36x+332=0 are x=-18+2sqrt(2)i,x=-18-2sqrt(2)i

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x^{2} + 36 x + 332 = 0

x = - 18 + 22 i, x = - 18 - 22 i

Solution steps

x^{2} + 36 x + 332 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 36 \pm 3 6 ^{2} - 4 \cdot 1 \cdot 332}{2 \cdot 1}

Simplify

3 6^{2} - 4 \cdot 1 \cdot 332 : 42 i

x_{1, 2} = \frac{- 36 \pm 4 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 36 + 4 2 i}{2 \cdot 1}, x_{2} = \frac{- 36 - 4 2 i}{2 \cdot 1}

x = \frac{- 36 + 4 2 i}{2 \cdot 1} : - 18 + 22 i

x = \frac{- 36 - 4 2 i}{2 \cdot 1} : - 18 - 22 i

The solutions to the quadratic equation are:

x = - 18 + 22 i, x = - 18 - 22 i

x^{2} + 7 x - 18 = 0

13 x^{2} - 27 = 0

2 x^{2} + 5 = 4 x

2 x^{2} + 13 x + 8 = 0

3 x^{2} = - x - 1

What are the solutions to the equation x^2+36x+332=0 ?
The solutions to the equation x^2+36x+332=0 are x=-18+2sqrt(2)i,x=-18-2sqrt(2)i
Find the zeros of x^2+36x+332=0
The zeros of x^2+36x+332=0 are x=-18+2sqrt(2)i,x=-18-2sqrt(2)i