(x+3)/(1-x)=(x+1)/(x+2)

Lösung

\frac{x + 3}{1 - x} = \frac{x + 1}{x + 2}

x = - \frac{5}{4} + i \frac{15}{4}, x = - \frac{5}{4} - i \frac{15}{4}

Schritte zur Lösung

\frac{x + 3}{1 - x} = \frac{x + 1}{x + 2}

Kreuzmultiplizieren

(x + 3) (x + 2) = (1 - x) (x + 1)

Löse

(x + 3) (x + 2) = (1 - x) (x + 1) : x = - \frac{5}{4} + i \frac{15}{4}, x = - \frac{5}{4} - i \frac{15}{4}

x = - \frac{5}{4} + i \frac{15}{4}, x = - \frac{5}{4} - i \frac{15}{4}

\frac{x - 12}{3 - x} = \frac{x + 4}{x + 7}

\frac{1}{x} + 3 = \frac{2}{x}

\frac{2}{x} - \frac{3}{2} = \frac{7}{2 x}

6 = x^{3} - \frac{4}{x}

\frac{1}{x} + \frac{1}{x - 8} = \frac{1}{3}