根 (3x^2+ax+a+3)/(x^2+x-2)

解

根

\frac{3 x ^{2} + a x + a + 3}{x ^{2} + x - 2}

x = \frac{- a + a ^{2} - 12 ( a + 3 )}{6}, x = \frac{- a - a ^{2} - 12 ( a + 3 )}{6}

解答ステップ

\frac{3 x ^{2} + a x + a + 3}{x ^{2} + x - 2}

根はx軸の切片である

(y = 0)

\frac{3 x ^{2} + a x + a + 3}{x ^{2} + x - 2} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

3 x^{2} + a x + a + 3 = 0

解く

3 x^{2} + a x + a + 3 = 0 : x = \frac{- a + a ^{2} - 12 ( a + 3 )}{6}, x = \frac{- a - a ^{2} - 12 ( a + 3 )}{6}

x = \frac{- a + a ^{2} - 12 ( a + 3 )}{6}, x = \frac{- a - a ^{2} - 12 ( a + 3 )}{6}