e^{x+1}=10^{2x}

解答

e^{x + 1} = 1 0^{2 x}

x = \frac{1}{2 ln ( 10 ) - 1}

十进制

x = 0.27737 \dots

求解步骤

e^{x + 1} = 1 0^{2 x}

使用指数运算法则

x + 1 = 2 x ln (10)

解

x + 1 = 2 x ln (10) : x = \frac{1}{2 ln ( 10 ) - 1}

x = \frac{1}{2 ln ( 10 ) - 1}

e^{2 x + 1} = 11

3^{x} + \frac{1}{3 ^{x + 1}} = \frac{28}{9}

so l v e f or x, x r - e^{x} = 0

8^{x} = \frac{1}{2}

1 6^{x} + 4^{x} - 6 = 0