1024^x=64^{2x-3}

Lösung

102 4^{x} = 6 4^{2 x - 3}

x = 9

Schritte zur Lösung

102 4^{x} = 6 4^{2 x - 3}

Wende Exponentenregel an

5 x = 3 (2 x - 3)

Löse

5 x = 3 (2 x - 3) : x = 9

x = 9

1 1^{3 x - 2} = 65

3^{x} - 3^{x - 1} - 7 \cdot 3^{x - 3} = 33

3 e^{- x} x^{2} - e^{- x} x^{3} = 0

8^{x + 3} = \frac{1}{16}

3^{2 x - 1} = 2^{x + 3}