4^x=32^{2+x}

Lösung

4^{x} = 3 2^{2 + x}

x = - \frac{10}{3}

Dezimale

x = - 3.33333 \dots

Schritte zur Lösung

4^{x} = 3 2^{2 + x}

Wende Exponentenregel an

2 x = 5 (2 + x)

Löse

2 x = 5 (2 + x) : x = - \frac{10}{3}

x = - \frac{10}{3}

5^{3 x + 2} + 3 \times 5^{6 x + 2} - 100 = 0

(24)^{x} = 5.76

8^{x + 3} = 1 6^{x - 1}

8^{\frac{5}{6}} - 8^{\frac{1}{2}} = 8^{m}

3^{6 - x} = 3^{3 x - 2}