32^x=(1/128)^{x-4}

Lösung

3 2^{x} = (\frac{1}{128})^{x - 4}

x = \frac{7}{3}

Dezimale

x = 2.33333 \dots

Schritte zur Lösung

3 2^{x} = (\frac{1}{128})^{x - 4}

Wende Exponentenregel an

5 x = - 7 (x - 4)

Löse

5 x = - 7 (x - 4) : x = \frac{7}{3}

x = \frac{7}{3}

x \cdot e^{x} = 0

4^{x + 3} \times 8^{2 x - 1} = 2

5^{2 x + 1} + 3 \cdot 5^{6 x - 3} = 500

5 e^{- 0.13 t} = 1.7

8^{x - 3} = 16