解
z4=−7+24i
解
z=5cos(4−arctan(724)+π)+5isin(4−arctan(724)+π),z=5cos(4−arctan(724)+3π)+5isin(4−arctan(724)+3π),z=5cos(4−arctan(724)+5π)+5isin(4−arctan(724)+5π),z=5cos(4−arctan(724)+7π)+5isin(4−arctan(724)+7π)
解答ステップ
z4=−7+24i
zn=aの場合, 解は zk=n∣a∣(cos(narg(a)+2kπ)+isin(narg(a)+2kπ)),
k=0,1,…,n−1
以下のため: n=4,a=−7+24i∣a∣=25
arg(a)=−arctan(724)+π
z=425(cos(4−arctan(724)+π+2⋅0π)+isin(4−arctan(724)+π+2⋅0π)),z=425(cos(4−arctan(724)+π+2⋅1π)+isin(4−arctan(724)+π+2⋅1π)),z=425(cos(4−arctan(724)+π+2⋅2π)+isin(4−arctan(724)+π+2⋅2π)),z=425(cos(4−arctan(724)+π+2⋅3π)+isin(4−arctan(724)+π+2⋅3π))
簡素化 425(cos(4−arctan(724)+π+2⋅0π)+isin(4−arctan(724)+π+2⋅0π)):5cos(4−arctan(724)+π)+5isin(4−arctan(724)+π)
簡素化 425(cos(4−arctan(724)+π+2⋅1π)+isin(4−arctan(724)+π+2⋅1π)):5cos(4−arctan(724)+3π)+5isin(4−arctan(724)+3π)
簡素化 425(cos(4−arctan(724)+π+2⋅2π)+isin(4−arctan(724)+π+2⋅2π)):5cos(4−arctan(724)+5π)+5isin(4−arctan(724)+5π)
簡素化 425(cos(4−arctan(724)+π+2⋅3π)+isin(4−arctan(724)+π+2⋅3π)):5cos(4−arctan(724)+7π)+5isin(4−arctan(724)+7π)
z=5cos(4−arctan(724)+π)+5isin(4−arctan(724)+π),z=5cos(4−arctan(724)+3π)+5isin(4−arctan(724)+3π),z=5cos(4−arctan(724)+5π)+5isin(4−arctan(724)+5π),z=5cos(4−arctan(724)+7π)+5isin(4−arctan(724)+7π)