a^3=3^9× 12^3× 21^6

Lösung

a^{3} = 3^{9} \cdot 1 2^{3} \cdot 2 1^{6}

a = 3 2.9171 E 15, a = - 3 2.9171 E 15 \frac{1}{2} + 3 2.9171 E 15 \frac{3}{2} i, a = - 3 2.9171 E 15 \frac{1}{2} - 3 2.9171 E 15 \frac{3}{2} i

Schritte zur Lösung

a^{3} = 3^{9} \cdot 1 2^{3} \cdot 2 1^{6}

Vereinfache

3^{9} \cdot 1 2^{3} \cdot 2 1^{6} : 2.9171 E 15

Für

x^{3} = f (a)

sind die Lösungen

x = 3 f (a), 3 f (a) \frac{- 1 - 3 i}{2}, 3 f (a) \frac{- 1 + 3 i}{2}

a = 3 2.9171 E 15, a = 3 2.9171 E 15 \frac{- 1 + 3 i}{2}, a = 3 2.9171 E 15 \frac{- 1 - 3 i}{2}

Vereinfache

3 2.9171 E 15 \frac{- 1 + 3 i}{2} : - 3 2.9171 E 15 \frac{1}{2} + 3 2.9171 E 15 \frac{3}{2} i

Vereinfache

3 2.9171 E 15 \frac{- 1 - 3 i}{2} : - 3 2.9171 E 15 \frac{1}{2} - 3 2.9171 E 15 \frac{3}{2} i

a = 3 2.9171 E 15, a = - 3 2.9171 E 15 \frac{1}{2} + 3 2.9171 E 15 \frac{3}{2} i, a = - 3 2.9171 E 15 \frac{1}{2} - 3 2.9171 E 15 \frac{3}{2} i

x = - x^{3}

x^{3} + 2 x^{2} - 40 x + 64 = 0

z^{4} = - 83 + 8 i

2 = \frac{4}{3} π r^{3}

1500 = 986 (1 + x)^{3}