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人気のある代数 >

solvefor y,6-x^2-y^2=sqrt(x^2+y^2)

解

解く

y, 6 - x^{2} - y^{2} = x^{2} + y^{2}

解

y = - x^{2} + 4 {- 2 \leq x \leq 2}, y = - - x^{2} + 4 {- 2 \leq x \leq 2}

解答ステップ

6 - x^{2} - y^{2} = x^{2} + y^{2}

両辺を2乗する:

2 y^{2} x^{2} - 12 x^{2} + x^{4} - 12 y^{2} + y^{4} + 36 = x^{2} + y^{2}

2 y^{2} x^{2} - 12 x^{2} + x^{4} - 12 y^{2} + y^{4} + 36 = x^{2} + y^{2}

解く

2 y^{2} x^{2} - 12 x^{2} + x^{4} - 12 y^{2} + y^{4} + 36 = x^{2} + y^{2} : y = - x^{2} + 9, y = - - x^{2} + 9, y = - x^{2} + 4, y = - - x^{2} + 4

y = - x^{2} + 9, y = - - x^{2} + 9, y = - x^{2} + 4, y = - - x^{2} + 4

解を検算する:

y = - x^{2} + 9

偽

, y = - - x^{2} + 9

偽

, y = - x^{2} + 4 {- 2 \leq x \leq 2}, y = - - x^{2} + 4 {- 2 \leq x \leq 2}

解答は

y = - x^{2} + 4 {- 2 \leq x \leq 2}, y = - - x^{2} + 4 {- 2 \leq x \leq 2}

グラフ

人気の例

sqrt(8x+24)-6=-2

8 x + 24 - 6 = - 2

x + 8 + 2 = 5

sqrt(x)=sqrt(6x-15)

x = 6 x - 15

1/2 x^2=sqrt(2x)+1

\frac{1}{2} x^{2} = 2 x + 1

(-2x^2+100)/(sqrt(100-x^2))=0

\frac{- 2 x ^{2} + 100}{100 - x ^{2}} = 0