log_{3}(x^2-4x+3)=1

Lösung

lo g_{3} (x^{2} - 4 x + 3) = 1

x = 4, x = 0

Schritte zur Lösung

lo g_{3} (x^{2} - 4 x + 3) = 1

Wende die log Regel an

x^{2} - 4 x + 3 = 3

Löse

x^{2} - 4 x + 3 = 3 : x = 4, x = 0

x = 4, x = 0

- lo g_{3} (2 - x) = 3

ln (x^{2} - 16) = 0

- 6 lo g_{12} (x - 5) = - 6

2 \cdot lo g_{2} (3 x - 7) = 10

4 ln (x^{2}) - 7 ln (x) + ln (x + 3) = 0