log_{7}(x^2-3x+3)=0

Lösung

lo g_{7} (x^{2} - 3 x + 3) = 0

x = 2, x = 1

Schritte zur Lösung

lo g_{7} (x^{2} - 3 x + 3) = 0

Wende die log Regel an

x^{2} - 3 x + 3 = 1

Löse

x^{2} - 3 x + 3 = 1 : x = 2, x = 1

x = 2, x = 1

lo g_{3} (7 x - 15) = 3

lo g_{x} (\frac{27}{8}) = 3

lo g_{2} (x) - lo g_{2} (x - 3) = 1

ln (x) = 1 - ln (x + 3)

lo g_{\frac{1}{4}} (3 x + 7) = - 2