What is the answer to ln(x^2+1)=8 ?

The answer to ln(x^2+1)=8 is x=sqrt(e^8-1),x=-sqrt(e^8-1)

Solve for x: ln(x^2+1)=8

The solution is x=sqrt(e^8-1),x=-sqrt(e^8-1)

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ln (x^{2} + 1) = 8

x = e^{8} - 1, x = - e^{8} - 1

Decimal

x = 54.58899 \dots, x = - 54.58899 \dots

Solution steps

ln (x^{2} + 1) = 8

Apply log rules

x^{2} + 1 = e^{8}

Solve

x^{2} + 1 = e^{8} : x = e^{8} - 1, x = - e^{8} - 1

x = e^{8} - 1, x = - e^{8} - 1

ln (x + 8) = 3

8 + lo g_{8} (x) = 8

lo g_{10} (1 0^{x} + 2) = 2 x + 1

lo g_{10} (x) = - 1.5

3 lo g_{10} (2 x + 6) = 6

What is the answer to ln(x^2+1)=8 ?
The answer to ln(x^2+1)=8 is x=sqrt(e^8-1),x=-sqrt(e^8-1)
Solve for x: ln(x^2+1)=8
The solution is x=sqrt(e^8-1),x=-sqrt(e^8-1)