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Popular >

15log_{2}(x-3)=2x+5

Solution

15 lo g_{2} (x - 3) = 2 x + 5

Solution

x = - \frac{15 W _{- 1} ( - \frac{2 e ^{\frac{11 l n ( 2 )}{15}} l n ( 2 )}{15} ) - 6 ln ( 2 )}{2 ln ( 2 )}, x = - \frac{15 W _{0} ( - \frac{2 e ^{\frac{11 l n ( 2 )}{15}} l n ( 2 )}{15} ) - 6 ln ( 2 )}{2 ln ( 2 )}

+1

Decimal

x = 35, x = 5

Solution steps

15 lo g_{2} (x - 3) = 2 x + 5

Divide both sides by

15

lo g_{2} (x - 3) = \frac{2 x + 5}{15}

If

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

2^{l o g_{2} (x - 3)} = 2^{\frac{2 x + 5}{15}}

Simplify

2^{l o g_{2} (x - 3)} : x - 3

x - 3 = 2^{\frac{2 x + 5}{15}}

Solve

x - 3 = 2^{\frac{2 x + 5}{15}} : x = - \frac{15 W _{- 1} ( - \frac{2 e ^{\frac{11 l n ( 2 )}{15}} l n ( 2 )}{15} ) - 6 ln ( 2 )}{2 ln ( 2 )}, x = - \frac{15 W _{0} ( - \frac{2 e ^{\frac{11 l n ( 2 )}{15}} l n ( 2 )}{15} ) - 6 ln ( 2 )}{2 ln ( 2 )}

x = - \frac{15 W _{- 1} ( - \frac{2 e ^{\frac{11 l n ( 2 )}{15}} l n ( 2 )}{15} ) - 6 ln ( 2 )}{2 ln ( 2 )}, x = - \frac{15 W _{0} ( - \frac{2 e ^{\frac{11 l n ( 2 )}{15}} l n ( 2 )}{15} ) - 6 ln ( 2 )}{2 ln ( 2 )}

Verify Solutions:

x = - \frac{15 W _{- 1} ( - \frac{2 e ^{\frac{11 l n ( 2 )}{15}} l n ( 2 )}{15} ) - 6 ln ( 2 )}{2 ln ( 2 )}

True

, x = - \frac{15 W _{0} ( - \frac{2 e ^{\frac{11 l n ( 2 )}{15}} l n ( 2 )}{15} ) - 6 ln ( 2 )}{2 ln ( 2 )}

True

The solutions are

x = - \frac{15 W _{- 1} ( - \frac{2 e ^{\frac{11 l n ( 2 )}{15}} l n ( 2 )}{15} ) - 6 ln ( 2 )}{2 ln ( 2 )}, x = - \frac{15 W _{0} ( - \frac{2 e ^{\frac{11 l n ( 2 )}{15}} l n ( 2 )}{15} ) - 6 ln ( 2 )}{2 ln ( 2 )}

Graph

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lo g_{4} (x^{2} + 8) = 2

ln (4 x) = 2.1

lo g_{x} (16) = 12

5 ln (2 x - 7) - 6 = 4

Frequently Asked Questions (FAQ)

What is the answer to 15log_{2}(x-3)=2x+5 ?
The answer to 15log_{2}(x-3)=2x+5 is
Solve for x: 15log_{2}(x-3)=2x+5
The solution is