因数 3(a+b)^2+11(a+b)-4

解

因数

3 (a + b)^{2} + 11 (a + b) - 4

(3 (a + b) - 1) (a + b + 4)

解答ステップ

3 (a + b)^{2} + 11 (a + b) - 4

式をグループに分ける

= (3 (a + b)^{2} - (a + b)) + (12 (a + b) - 4)

(a + b)

を

3 (a + b)^{2} - (a + b) : (a + b) (3 (a + b) - 1)

からくくり出す

4

を

12 (a + b) - 4 : 4 (3 (a + b) - 1)

からくくり出す

= (a + b) (3 (a + b) - 1) + 4 (3 (a + b) - 1)

共通項をくくり出す

3 (a + b) - 1

= (3 (a + b) - 1) ((a + b) + 4)

改良

= (a + b + 4) (3 (a + b) - 1)