因数 16(x^2+1)^2-4(2x)^2

解

因数

16 (x^{2} + 1)^{2} - 4 (2 x)^{2}

16 (x^{2} + x + 1) (x^{2} - x + 1)

解答ステップ

16 (x^{2} + 1)^{2} - 4 (2 x)^{2}

共通項をくくり出す

4 : 4 (4 (x^{2} + 1)^{2} - (2 x)^{2})

= 4 (4 (x^{2} + 1)^{2} - (2 x)^{2})

因数

4 (x^{2} + 1)^{2} - (2 x)^{2} : 4 (x^{2} + x + 1) (x^{2} - x + 1)

= 4 \cdot 4 (x^{2} + x + 1) (x^{2} - x + 1)

数を乗じる:

4 \cdot 4 = 16

= 16 (x^{2} + x + 1) (x^{2} - x + 1)