2x^2+5x+3<0

Lösung

2 x^{2} + 5 x + 3 < 0

- \frac{3}{2} < x < - 1

Intervall-Notation

(- \frac{3}{2}, - 1)

Dezimale

- 1.5 < x < - 1

Schritte zur Lösung

2 x^{2} + 5 x + 3 < 0

Faktorisiere

2 x^{2} + 5 x + 3 : (x + 1) (2 x + 3)

(x + 1) (2 x + 3) < 0

Identifiziere die Intervalle

- \frac{3}{2} < x < - 1

8 x - 2 = 0

8 x^{2} = 12 x + 4

4 (x - 4) = 19 - 7 (4 x + 1)

2 (3 y - 4) = 3 (y - \frac{2}{3})

- \frac{x}{3} + 21 = 0