(x+2)^2(x+5)(x+9)<0

Lösung

(x + 2)^{2} (x + 5) (x + 9) < 0

- 9 < x < - 5

Intervall-Notation

(- 9, - 5)

Schritte zur Lösung

(x + 2)^{2} (x + 5) (x + 9) < 0

Identifiziere die Intervalle

- 9 < x < - 5

10 x - \frac{8}{3} - 4 x = 6 x

f a c t or (x - 3 y)^{2} - (y - x)^{2}

\frac{2}{3} = \frac{x}{4}

1 + 2 n \geq 7

- 4 x + 9 - x < - 3