x^2+10x+24=0

解答

x^{2} + 10 x + 24 = 0

x = - 4, x = - 6

求解步骤

x^{2} + 10 x + 24 = 0

使用求根公式求解

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 24 = 2

x_{1, 2} = \frac{- 10 \pm 2}{2 \cdot 1}

将解分隔开

x_{1} = \frac{- 10 + 2}{2 \cdot 1}, x_{2} = \frac{- 10 - 2}{2 \cdot 1}

x = \frac{- 10 + 2}{2 \cdot 1} : - 4

x = \frac{- 10 - 2}{2 \cdot 1} : - 6

二次方程组的解是:

x = - 4, x = - 6

0 = - 16 t^{2} + 32 t + 48

s im pl i f y (\frac{e ^{7}}{e ^{4}})^{- 1}

f a c t or 2 x^{2} + 44 x + 242

f a c t or x^{4} + 12 x^{2} + 20

s im pl i f y - 4 (- 4)