zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的代数 >

3t^2-14t+22=0

解答

3 t^{2} - 14 t + 22 = 0

解答

t = \frac{7}{3} + i \frac{17}{3}, t = \frac{7}{3} - i \frac{17}{3}

求解步骤

3 t^{2} - 14 t + 22 = 0

使用求根公式求解

t_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 3 \cdot 22}{2 \cdot 3}

化简

(- 14)^{2} - 4 \cdot 3 \cdot 22 : 217 i

t_{1, 2} = \frac{- ( - 14 ) \pm 2 17 i}{2 \cdot 3}

将解分隔开

t_{1} = \frac{- ( - 14 ) + 2 17 i}{2 \cdot 3}, t_{2} = \frac{- ( - 14 ) - 2 17 i}{2 \cdot 3}

t = \frac{- ( - 14 ) + 2 17 i}{2 \cdot 3} : \frac{7}{3} + i \frac{17}{3}

t = \frac{- ( - 14 ) - 2 17 i}{2 \cdot 3} : \frac{7}{3} - i \frac{17}{3}

二次方程组的解是:

t = \frac{7}{3} + i \frac{17}{3}, t = \frac{7}{3} - i \frac{17}{3}

作图

流行的例子

log_{7}(2-x)<= log_{7}(3x+6)

lo g_{7} (2 - x) \leq lo g_{7} (3 x + 6)

x - 1 < \frac{2}{∣ x ∣}

7 - 2 x^{2} = - 7

化简 (8x^6)^{-2/3}

s im pl i f y (8 x^{6})^{- \frac{2}{3}}

4(u+2)-u=2(u-1)+9

4 (u + 2) - u = 2 (u - 1) + 9