q^2+q=0

解

q^{2} + q = 0

q = 0, q = - 1

解答ステップ

q^{2} + q = 0

解くとthe二次式

q_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot 0 = 1

q_{1, 2} = \frac{- 1 \pm 1}{2 \cdot 1}

解を分離する

q_{1} = \frac{- 1 + 1}{2 \cdot 1}, q_{2} = \frac{- 1 - 1}{2 \cdot 1}

q = \frac{- 1 + 1}{2 \cdot 1} : 0

q = \frac{- 1 - 1}{2 \cdot 1} : - 1

二次equationの解:

q = 0, q = - 1