因数 1/64 x^2-4/81

解

因数

\frac{1}{64} x^{2} - \frac{4}{81}

(\frac{1}{8} x + \frac{2}{9}) (\frac{1}{8} x - \frac{2}{9})

解答ステップ

\frac{1}{64} x^{2} - \frac{4}{81}

\frac{1}{64} x^{2} = (\frac{1}{8} x)^{2}

\frac{4}{81} = (\frac{2}{9})^{2}

= (\frac{1}{8} x)^{2} - (\frac{2}{9})^{2}

2乗の差の公式を適用する:

x^{2} - y^{2} = (x + y) (x - y)

(\frac{1}{8} x)^{2} - (\frac{2}{9})^{2} = (\frac{1}{8} x + \frac{2}{9}) (\frac{1}{8} x - \frac{2}{9})

= (\frac{1}{8} x + \frac{2}{9}) (\frac{1}{8} x - \frac{2}{9})