What are the solutions to the equation 2x^2+11x+15=0 ?

The solutions to the equation 2x^2+11x+15=0 are x=-5/2 ,x=-3

Find the zeros of 2x^2+11x+15=0

The zeros of 2x^2+11x+15=0 are x=-5/2 ,x=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} + 11 x + 15 = 0

x = - \frac{5}{2}, x = - 3

Decimal Notation

x = - 2.5, x = - 3

Solution steps

2 x^{2} + 11 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 2 \cdot 15}{2 \cdot 2}

1 1^{2} - 4 \cdot 2 \cdot 15 = 1

x_{1, 2} = \frac{- 11 \pm 1}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 11 + 1}{2 \cdot 2}, x_{2} = \frac{- 11 - 1}{2 \cdot 2}

x = \frac{- 11 + 1}{2 \cdot 2} : - \frac{5}{2}

x = \frac{- 11 - 1}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

x = - \frac{5}{2}, x = - 3

(9 x + 10)^{2} - 4 x (9 x + 10)

4 m^{2} - 12 m + 9

20 - 9 x - 20 x^{2}

\frac{3}{3 x - 2} < 0

\frac{x - 5}{2} \leq x

What are the solutions to the equation 2x^2+11x+15=0 ?
The solutions to the equation 2x^2+11x+15=0 are x=-5/2 ,x=-3
Find the zeros of 2x^2+11x+15=0
The zeros of 2x^2+11x+15=0 are x=-5/2 ,x=-3