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受欢迎的代数 >

-25t^2+200t+400=0

解答

- 25 t^{2} + 200 t + 400 = 0

解答

t = - 4 (2 - 1), t = 4 (1 + 2)

+1

十进制

t = - 1.65685 \dots, t = 9.65685 \dots

求解步骤

- 25 t^{2} + 200 t + 400 = 0

使用求根公式求解

t_{1, 2} = \frac{- 200 \pm 20 0 ^{2} - 4 ( - 25 ) \cdot 400}{2 ( - 25 )}

20 0^{2} - 4 (- 25) \cdot 400 = 2002

t_{1, 2} = \frac{- 200 \pm 200 2}{2 ( - 25 )}

将解分隔开

t_{1} = \frac{- 200 + 200 2}{2 ( - 25 )}, t_{2} = \frac{- 200 - 200 2}{2 ( - 25 )}

t = \frac{- 200 + 200 2}{2 ( - 25 )} : - 4 (2 - 1)

t = \frac{- 200 - 200 2}{2 ( - 25 )} : 4 (1 + 2)

二次方程组的解是:

t = - 4 (2 - 1), t = 4 (1 + 2)

作图

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