What are the solutions to the equation (x+1)(x+1)=1 ?

The solutions to the equation (x+1)(x+1)=1 are x=0,x=-2

Find the zeros of (x+1)(x+1)=1

The zeros of (x+1)(x+1)=1 are x=0,x=-2

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(x + 1) (x + 1) = 1

x = 0, x = - 2

Solution steps

(x + 1) (x + 1) = 1

Simplify

(x + 1)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = 1 : x = 0

Solve

x + 1 = - 1 : x = - 2

The solutions to the quadratic equation are:

x = 0, x = - 2

5 x^{2} + 470 = - 100 x

3 ∣ 2 x - 7 ∣ = 3

\frac{3 X + 2}{X - 1} > 0

3 x^{2} + 21 x + 18 = 0

∣ x + 3 ∣ \leq - x + 1

What are the solutions to the equation (x+1)(x+1)=1 ?
The solutions to the equation (x+1)(x+1)=1 are x=0,x=-2
Find the zeros of (x+1)(x+1)=1
The zeros of (x+1)(x+1)=1 are x=0,x=-2