What are the solutions to the equation 3x^2+21x+18=0 ?

The solutions to the equation 3x^2+21x+18=0 are x=-1,x=-6

Find the zeros of 3x^2+21x+18=0

The zeros of 3x^2+21x+18=0 are x=-1,x=-6

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3 x^{2} + 21 x + 18 = 0

x = - 1, x = - 6

Solution steps

3 x^{2} + 21 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 21 \pm 2 1 ^{2} - 4 \cdot 3 \cdot 18}{2 \cdot 3}

2 1^{2} - 4 \cdot 3 \cdot 18 = 15

x_{1, 2} = \frac{- 21 \pm 15}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 21 + 15}{2 \cdot 3}, x_{2} = \frac{- 21 - 15}{2 \cdot 3}

x = \frac{- 21 + 15}{2 \cdot 3} : - 1

x = \frac{- 21 - 15}{2 \cdot 3} : - 6

The solutions to the quadratic equation are:

x = - 1, x = - 6

∣ x + 3 ∣ \leq - x + 1

54 + 24

x^{2} + 1 0^{2} = 2 6^{2}

2 x + 1 > 3

\frac{( 3 x y ) ^{2} ( 2 x ^{4} y ^{3} )}{6 x ^{8} y}

What are the solutions to the equation 3x^2+21x+18=0 ?
The solutions to the equation 3x^2+21x+18=0 are x=-1,x=-6
Find the zeros of 3x^2+21x+18=0
The zeros of 3x^2+21x+18=0 are x=-1,x=-6