x(4-5x)<= 0

Lösung

x (4 - 5 x) \leq 0

x \leq 0 or x \geq \frac{4}{5}

Intervall-Notation

(- \infty, 0] \cup [\frac{4}{5}, \infty)

Dezimale

x \leq 0 or x \geq 0.8

Schritte zur Lösung

x (4 - 5 x) \leq 0

Identifiziere die Intervalle

x \leq 0 or x \geq \frac{4}{5}

\frac{1}{x - 2} + \frac{3}{4 x - 36} \geq 0

f a c t or p^{2} - 2 p - 15

7 x^{2} - 42 x = 0

7 x^{2} = - x

x^{2} + 3 x - 1 = 3