(5pi)/3 x+(40pi)/3 =0

解答

\frac{5 π}{3} x + \frac{40 π}{3} = 0

x = - 8

求解步骤

\frac{5 π}{3} x + \frac{40 π}{3} = 0

将

\frac{40 π}{3}

到右边

\frac{5 π}{3} x = - \frac{40 π}{3}

在两边乘以

3

5 π x = - 40 π

两边除以

5 π

x = - 8

f a c t or 9 x^{3} + 36 x^{2} - 4 x - 16

6 x^{2} - x = 35

\frac{4}{6} x - 4 x + \frac{8}{3} = \frac{4}{3}

f a c t or 4 a^{2} - 12 a - 8

s im pl i f y (3 (\frac{4 i}{n})^{2} + 8 (\frac{4 i}{n}) - 5) (\frac{4}{n})