faktorisieren 12m^2n+24m^3n^2-36m^4n+48m^5n^4

Lösung

faktorisieren

12 m^{2} n + 24 m^{3} n^{2} - 36 m^{4} n + 48 m^{5} n^{4}

12 m^{2} n (1 + 2 mn - 3 m^{2} + 4 m^{3} n^{3})

Schritte zur Lösung

12 m^{2} n + 24 m^{3} n^{2} - 36 m^{4} n + 48 m^{5} n^{4}

Wende Exponentenregel an:

a^{b + c} = a^{b} a^{c}

m^{3} n^{2} = m^{2} mnn, m^{4} n = m^{2} m^{2} n, m^{5} n^{4} = m^{2} m^{3} n n^{3}

= 12 m^{2} n + 24 m^{2} mnn - 36 m^{2} m^{2} n + 48 m^{2} m^{3} n n^{3}

Schreibe

48

um:

4 \cdot 12

Schreibe

- 36

um:

3 \cdot 12

= 12 m^{2} n + 2 \cdot 12 m^{2} mnn + 3 \cdot 12 m^{2} m^{2} n + 4 \cdot 12 m^{2} m^{3} n n^{3}

Klammere gleiche Terme aus

12 m^{2} n

= 12 m^{2} n (1 + 2 mn - 3 m^{2} + 4 m^{3} n^{3})

f a c t or m^{2} + 14 m n^{2} + 49 n^{4}

∣ x + 6 ∣ = - 3

2 t - 4 < - 6

s im pl i f y 15 - 6

f a c t or 14 x + 49